線上:28
演講網 | 使用者 | 登入   進階
1031 第三次化學會考考題影音講解  
格狀顯示
清單顯示
Outline:
 1.1)The distance between adjacent crests in an electromagnetic wave is calledamplitude frequency area median WavelengthAns:E
演講者: 洪國明
觀看 (514), 討論 (0)
演講日期: 2014-12-28
上架時間: 2015-01-23
上傳者: energy4104
00:15
Outline:
 1.2) Which of the following colors of electromagnetic radiation has the shortest wavelength?blue yellow green violet OrangeAns:D
演講者: 洪國明
觀看 (428), 討論 (0)
演講日期: 2014-12-28
上架時間: 2015-01-23
上傳者: energy4104
00:18
Outline:
 1.3) Which kind of electromagnetic radiation contains the greatest energy per photonA) infrared radiationB) X-raysC) microwavesD) visible lightE) gamma raysAns:E
演講者: 洪國明
觀看 (384), 討論 (0)
演講日期: 2014-12-28
上架時間: 2015-01-23
上傳者: energy4104
00:28
Outline:
 1.4) Calculate the energy of the red light emitted by a neon atom with a wavelength of 703.2 nm. (Planck’s Constant h = 6.626 × 10−34 J · s)A) 2.83 × 10-19 JB) 4.27 × 10-19 JC) 6.45 × 10-19 JD) 3.54 × 10-19 JE) 2.34 × 10-19 JAns:A
演講者: 洪國明
觀看 (460), 討論 (0)
演講日期: 2014-12-28
上架時間: 2015-01-23
上傳者: energy4104
00:50
Outline:
 1.5) A nitrogen gas laser pulse with a wavelength of 337 nm contains 3.83 mJ of energy. How many photons does it contain?3.83 × 109 5.90 × 103 7.44 × 1012 9.25 × 1018 6.49 × 1015Ans:E
演講者: 洪國明
觀看 (402), 討論 (0)
演講日期: 2014-12-28
上架時間: 2015-01-23
上傳者: energy4104
00:54
Outline:
 1.6) Which of the following statements is TRUE?A) An orbital is the volume in which we are most likely to find an electron.B) The emission spectrum of a particular element is always the same and can be used to identify the element.C) Part of the Bohr model proposed that electrons in the hydrogen atom are located in ʺstationary statesʺ or particular orbits around the nucleus.D) The uncertainty principle states that we can never know both the exact location and speed of an electron.E) All of the above are true.Ans:E
演講者: 洪國明
觀看 (353), 討論 (0)
演講日期: 2014-12-28
上架時間: 2015-01-23
上傳者: energy4104
01:29
Outline:
 1.7) Calculate the wavelength of a baseball (m = 155 g) moving at 32.5 m/s. (1 J = 1 kg · m2/s2)A) 2.68 × 10-34 mB) 1.32 × 10-34 mC) 3.57 × 10-32 mD) 7.60 × 10-36 mE) 2.15 × 10-32 mAns:B
演講者: 洪國明
觀看 (323), 討論 (0)
演講日期: 2014-12-28
上架時間: 2015-01-23
上傳者: energy4104
00:32
Outline:
 1.8) It is possible to determine the ionization energy for hydrogen using the Bohr equation. Calculate the ionization energy (in kJ) for a mole of hydrogen atoms, making the assumption that ionization is the transition from n = 1 to n = ∞. (Rydberg constant RH = 2.18 x 10-18 J)3.62 × 103 kJ B) 5.33 × 103 kJ C) 1.31 × 103 kJ D) 2.76 × 103 kJ E) 7.62 × 103 kJAns:C
演講者: 洪國明
觀看 (274), 討論 (0)
演講日期: 2014-12-28
上架時間: 2015-01-23
上傳者: energy4104
01:06
Outline:
 1.9) Which of the following statements is TRUE?A) An orbital is the path that an electron follows during its movement in an atom.B) The magnetic quantum number (ml) describes the orientation of the orbital.C) The principal quantum number (n) describes the shape of an orbital.D) The angular momentum quantum number (l) describes the the size and energy associated with an orbital.E) All of the above are true.Ans:B
 2.Slide 10
 3.9) Which of the following statements is TRUE?A) An orbital is the path that an electron follows during its movement in an atom.B) The magnetic quantum number (ml) describes the orientation of the orbital.C) The principal quantum number (n) describes the shape of an orbital.D) The angular momentum quantum number (l) describes the the size and energy associated with an orbital.E) All of the above are true.Ans:B
演講者: 洪國明
觀看 (241), 討論 (0)
演講日期: 2014-12-28
上架時間: 2015-01-23
上傳者: energy4104
00:47
Outline:
 1.10) What value of l is represented by a d orbital?0 B) 2 C) 3 D) 1Ans:B
演講者: 洪國明
觀看 (225), 討論 (0)
演講日期: 2014-12-28
上架時間: 2015-01-23
上傳者: energy4104
00:39
Prev123Next